GRE Numeric Entry questions contribute to roughly 10% of GRE’s Quantitative Reasoning and must be duly covered in a sincere GRE prep course. NE is not a separate topic or concept but a distinct question format used to test the same quantitative concepts assessed by other GRE question types. Numerical entry questions are distinctive because they do not provide answer choices and require you to enter the correct numeric value directly, as an integer, decimal, or a fraction.
How Numeric Entry Questions Appear on the GRE
Correct Answer: 16
Correct Answer: 27/4
GRE-Style Practice Questions | Numeric Entry
Work through the exercise below, a set of GRE style numeric entry questions with clear explanations. Solve carefully without focusing on speed at this stage and target full accuracy. After you finish, study every explanation, review your incorrect and slow attempts, and extract maximum learning from the exercise.
All the best!
Practice Question 1 | GRE NE
When the decimal point of a certain positive decimal number is shifted one place to the right, the resulting number is 10 more than twice the original number. What is the original number?
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Written Explanation
Let the original number be n. We need to determine the value of n.
Shifting the decimal point one place to the right in a positive decimal number is equivalent to multiplying the number by 10.
Since shifting the decimal point of n one place to the right results in a number that is 10 more than twice of n,
10n = 2n + 10
8n = 10 n = 1.25
1.25 is the correct answer.
Practice Question 2 | GRE NE
ABCD is a rectangle and 3x – y/2x – y= 8/15. What is the value of x?
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Written Explanation
3x – y/2x – y= 8/15 We need to determine the value of x.
Since angles x and y lie on a straight line, x + y = 180.
Multiplying both sides by 7, we get; 7x + 7y = (7)(180) (Equation II)
Adding Equations I and II,
(29x – 7y) + (7x + 7y) = (7)(180)
36x = (7)(180) x = 35
35 is the correct answer.
Practice Question 3 | GRE NE
If (3m)(8n) = 816 where m and n are integers greater than 1, what is the value of m + n?
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Written Explanation
(3m)(8n) = 816
24mn = 816 mn = 34 We need to determine the value of m + n.
Since m and n are integers, {2, 17} is the only set of possible values for m and n.
Hence, m + n = 2 + 17 = 19.
19 is the correct answer.
Practice Question 4 | GRE NE
A line passes through the points (1, 5) and (3, 8). Another line is parallel to this line and has a y-intercept of 3. What is the x-coordinate of the point where this parallel line intersects the line y = 2x + 1?
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Written Explanation
Let the line passing through points (1, 5) and (3, 8) be line m.
Let the line parallel to line m be line n. We need to determine the x-coordinate of the point where the line n intersects the line y = 2x + 1.
Slope of line m = (8 – 5)/(3 – 1) = 3/2.
Since line n is parallel to line m, the slope of line n = the slope of line m = 3/2.
Using the slope-intercept form of a line, the equation of line n is, y = mx + c
Substituting slope 3/2 and y-intercept 3, y = (3x/2) + 3
At the point where line n intersects the line y = 2x + 1, the y-coordinate of the two lines will be the same.
2x + 1 = (3x/2) + 3
2x + 1 = (3x + 6)/2
4x + 2 = 3x + 6
4x – 3x = 6 – 2 x = 4
Hence, the x-coordinate of the point where the parallel line intersects the line y = 2x + 1 is 4.
4 is the correct answer.
Practice Question 5 | GRE NE
There are only 360 members of an endangered species of parrot surviving, all found in one of three zoos: the San Francisco Zoo, the Seattle Zoo, and the Hong Kong Zoo. If 5/12 of the surviving parrots are housed in the San Francisco Zoo and if four times as many are housed in the Seattle Zoo as in the Hong Kong Zoo, how many of these parrots are housed in the Seattle Zoo?
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Written Explanation
Let the number of parrots housed in the Hong Kong Zoo be n.
Since four times as many parrots are housed in the Seattle Zoo as in the Hong Kong Zoo, the number of parrots housed in the Seattle Zoo = 4n.
The total number of parrots = 360.
We need to determine the value of 4n.
Since 5/12 of the parrots are housed in the San Francisco Zoo, the number of parrots housed in the San Francisco Zoo = (5/12) × 360 = 150.
(The number of parrots housed in the San Francisco Zoo) + (The number of parrots housed in the Hong Kong Zoo) + (The number of parrots housed in the Seattle Zoo) = (Total number of parrots) 150 + n + 4n = 360
5n = 210 n = 42
Hence, the number of parrots housed in the Seattle Zoo = 4n = 4 × 42 = 168.
168 is the correct answer.
Additional Free GRE-style Numeric Entry Questions with Explanations:
